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Qus

. What will be the output of the following Python code?

s1={3, 4}

  s2={1, 2}  s3=set()  i=0  j=0  for i in s1:      for j in s2:          s3.add((i,j))          i+=1          j+=1

print(s3)

Qusनिम्नलिखित Python कोड का आउटपुट क्या होगा?

A. {(3, 4), (1, 2)}
B. Error
C. {(4, 2), (3, 1), (4, 1), (5, 2)}
D. {(3, 1), (4, 2)}

Solution

C. {(4, 2), (3, 1), (4, 1), (5, 2)}

Explanation

The code shown above finds the Cartesian product of the two sets, s1 and s2. The Cartesian product of these two sets is stored in a third set, that is, s3. Hence the output of this code is: {(4, 2), (3, 1), (4, 1), (5, 2)}.

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Qus
. What will be the output of the following Python code?

s1={3, 4}

s2={1, 2} s3=set() i=0 j=0 for i in s1: for j in s2: s3.add((i,j)) i+=1 j+=1

print(s3)
Qusनिम्नलिखित Python कोड का आउटपुट क्या होगा?

Solution

Explanation

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Qus. What will be the output of the following Python code? s1={3, 4} s2={1, 2} s3=set() i=0 j=0 for i in s1: for j in s2: s3.add((i,j)) i+=1 j+=1 print(s3) Qusनिम्नलिखित Python कोड का आउटपुट क्या होगा?

Solution

Explanation

Qus
. What will be the output of the following Python code?

s1={3, 4}

s2={1, 2} s3=set() i=0 j=0 for i in s1: for j in s2: s3.add((i,j)) i+=1 j+=1

print(s3)
Qusनिम्नलिखित Python कोड का आउटपुट क्या होगा?