O Level Exam : Practical Question
📝 HTML
🎨 CSS
⚡ Java Script
#include <math.h> #include <stdio.h> int main() { int low, high, number, originalNumber, rem, count = 0; double result = 0.0; printf("Enter two numbers(intervals): "); scanf("%d %d", &low, &high); printf("Armstrong numbers between %d and %d are: ", low, high); // iterate number from (low + 1) to (high - 1) // In each iteration, check if number is Armstrong for (number = low + 1; number < high; ++number) { originalNumber = number; // number of digits calculation while (originalNumber != 0) { originalNumber /= 10; ++count; } originalNumber = number; // result contains sum of nth power of individual digits while (originalNumber != 0) { rem = originalNumber % 10; result += pow(rem, count); originalNumber /= 10; } // check if number is equal to the sum of nth power of individual digits if ((int)result == number) { printf("%d ", number); } // resetting the values count = 0; result = 0; } return 0; }
▶ Run Code
🖥 Output: