What will be the output of the following Python code snippet?
x = 'abcd' for i in range(len(x)): x[i].upper() print (x)
abcd
ABCD
error
none of the mentioned
x = 'abcd' for i in range(len(x)): x = 'a' print(x)
a
abcd abcd abcd
a a a a
x = 'abcd' for i in range(len(x)): print(x) x = 'a'
abcd abcd abcd abcd
What will be the output of the following Python code?
d = {0: 'a', 1: 'b', 2: 'c'} for i in d: print(i)
0 1 2
a b c
0 a 1 b 2 c
d = {0: 'a', 1: 'b', 2: 'c'} for x, y in d.items(): print(x, y)
Option A
Option B
Option C
Option D
d = {0: 'a', 1: 'b', 2: 'c'} for x in d.keys(): print(d[x])
d = {0: 'a', 1: 'b', 2: 'c'} for x in d.values(): print(x)
d = {0: 'a', 1: 'b', 2: 'c'} for x in d.values(): print(d[x])
d = {0, 1, 2} for x in d.values(): print(x)
None None None
d = {0, 1, 2} for x in d: print(x)
{0, 1, 2} {0, 1, 2} {0, 1, 2}
for i in range(0): print(i)
0
no output
for i in range(2.0): print(i)
0.0 1.0
0 1
for i in range(int(2.0)): print(i)
for i in [1, 2, 3, 4][::-1]: print (i)
1 2 3 4
4 3 2 1
for i in ''.join(reversed(list('abcd'))): print (i)
a b c d
d c b a
for i in 'abcd'[::-1]: print (i)
x = 2 for i in range(x): x += 1 print (x)
0 1 2 3 4 …
3 4
x = 2 for i in range(x): x -= 2 print (x)
0 -2
for i in range(10): if i == 5: break else: print(i) else: print("Here")
0 1 2 3 4 Here
0 1 2 3 4 5 Here
0 1 2 3 4
1 2 3 4 5
for i in range(5): if i == 5: break else: print(i) else: print("Here")